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利用Postgresql 怎么查询表中的列名?针对这个问题,这篇文章详细介绍了相对应的分析和解答,希望可以帮助更多想解决这个问题的小伙伴找到更简单易行的方法。
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在testdb下执行下列sql语句,得到所有表的信息
select * from information_schema.columns where table_schema='public' and table_name<>'pg_stat_statements';
在testdb下执行下列sql语句,得到所有表的列名
select column_name from information_schema.columns where table_schema='public' and table_name<>'pg_stat_statements';
在testdb下执行下列sql语句,得到表"table"的列名
select column_name from information_schema.columns where table_schema='public' and table_name='table';
补充:PostgreSql数据库查询表信息/列信息(列ID/列名/数据类型/长度/精度/是否可以为null/默认值/是否自增/是否是主键/列描述)
查询表信息(表名/表描述)
select a.relname as name , b.description as value from pg_class a left join (select * from pg_description where objsubid =0 ) b on a.oid = b.objoid where a.relname in (select tablename from pg_tables where schemaname = 'public') order by a.relname asc
查询列信息(列ID/列名/数据类型/长度/精度/是否可以为null/默认值/是否自增/是否是主键/列描述)
select ordinal_position as Colorder,column_name as ColumnName,data_type as TypeName, coalesce(character_maximum_length,numeric_precision,-1) as Length,numeric_scale as Scale, case is_nullable when 'NO' then 0 else 1 end as CanNull,column_default as DefaultVal, case when position('nextval' in column_default)>0 then 1 else 0 end as IsIdentity, case when b.pk_name is null then 0 else 1 end as IsPK,c.DeText from information_schema.columns left join ( select pg_attr.attname as colname,pg_constraint.conname as pk_name from pg_constraint inner join pg_class on pg_constraint.conrelid = pg_class.oid inner join pg_attribute pg_attr on pg_attr.attrelid = pg_class.oid and pg_attr.attnum = pg_constraint.conkey[1] inner join pg_type on pg_type.oid = pg_attr.atttypid where pg_class.relname = '表名' and pg_constraint.contype='p' ) b on b.colname = information_schema.columns.column_name left join ( select attname,description as DeText from pg_class left join pg_attribute pg_attr on pg_attr.attrelid= pg_class.oid left join pg_description pg_desc on pg_desc.objoid = pg_attr.attrelid and pg_desc.objsubid=pg_attr.attnum where pg_attr.attnum>0 and pg_attr.attrelid=pg_class.oid and pg_class.relname='表名' )c on c.attname = information_schema.columns.column_name where table_schema='public' and table_name='表名' order by ordinal_position asc
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