python3自动打印出最新版本执行的mysql2redis实例-创新互联

我就废话不多说了，直接看代码吧！

#!/usr/bin/env python3
# -*- coding: utf-8 -*-
# 输出 mysql2redis 命令
# __author__ = caozhi
# create_time 2018-11-12,update_time 2019-12-12
# version = 2.0

import os
import re
import sys
import time
import fcntl
import subprocess
import requests

ip = "8.8.8.8"
urlnginxA = "http://8.8.8.8:81/version"
urlnginxB = "http://8.8.8.8:82/version"
defaultversion = {"module":"nginx","ver":"v0.0.0"}

def ApplicationInstance():
  global pidfile
  pidfile = open(os.path.realpath(__file__), "r")
  try:
    fcntl.flock(pidfile, fcntl.LOCK_EX | fcntl.LOCK_NB) #创建一个排他锁,并且所被锁住其他进程不会阻塞
    #print('continue...')
  except:
    print('error', 'The script was executed many times...')
    sys.exit(1)

def getversion(url):
  try:
    nginx_response = requests.get(url, timeout=3)
    if nginx_response.status_code == 200:
      data=nginx_response.json()
    else:
      print('\033[31m 接口响应非200，请重新确认执行，默认忽略本次接口的相应 %s http_code:%s\033[0m'%(url, nginx_response.status_code))
      data = defaultversion

except Exception as e:
  print('\033[31m 接口建联失败，请重新确认，默认忽略本次接口的相应 %s \033[0m'%url)
  print(e)
  data = defaultversion

finally:
  return data

def nginx_version(data):
  version = data['ver'].split('v')[1]
  return version

if __name__ == '__main__':
  ApplicationInstance()
  nginxA_data = getversion(urlnginxA)
  nginxB_data = getversion(urllnginxB)
  print('\033[33m nginxA_version \033[0m %s'%nginxA_data)
  print('\033[33m nginxB_version \033[0m %s'%nginxB_data)

versionA = nginx_version(nginxA_data)
versionB = nginx_version(nginxB_data)
d0=re.split('\.', versionA)
d2=re.split('\.', versionB)
d0=[int(d0[i]) for i in range(len(d0))]
d2=[int(d2[i]) for i in range(len(d2))]
print()

if(d0>d2):
  print('\033[35m nginxA \033[0m这个版本大 v{}'.format(versionA))
  print('\033[36m********* ↓ 这是要执行的mysql2redis的命令 请手动执行↓ ********* \033[0m')
  print('ssh {} "curl -v http://127.0.0.1:81/mysql2redis"'.format(ip))
if(d0                

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