c语言makeup函数 c语言mktime函数

C语言!和文件有关

#include "stdio.h"

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#include malloc.h

#include stdlib.h

struct Student

{

int num;

char name[20];

int score;

}student;

struct list

{

struct Student stu;

struct list *next;

};

struct list* creat(struct list *head,struct Student student)//建表

{

struct list *p1,*p2,*p;

p = head;

p1 = (struct list *)malloc(sizeof(struct list));

p1-stu = student;

if (head == NULL)

{

head = p1;

p1-next = NULL;

}

else

{

while (p-next != NULL)

{

p2 = p;

p = p-next;

}

if (head == p)

{

p-next = p1;

p1-next = NULL;

}

else

{

p2-next = p1;

p1-next = NULL;

}

}

return head;

}

void Print(struct list *head)//输出

{

FILE *fp;

fp = fopen("SCORE.DAT1","w");

if (fp == NULL)

{

printf("open file failed!\n");

exit(0);

}

struct list *p,*q;

p = head;

while (p != NULL)

{

fprintf(fp,"%d %s %d\n",p-stu.num,p-stu.name,p-stu.score);

q = p-next;

free(p);

p = q;

}

fclose(fp);

}

main()

{

struct list *head;

int makeup;

FILE *fp,*fpp;

head = NULL;

fp = fopen("SCORE.DAT","r");

fpp = fopen("BK.DAT","r");

if (fp == NULL)

{

printf("open file failed!\n");

exit(0);

}

if (fpp == NULL)

{

printf("open file failed!\n");

exit(0);

}

while (!feof(fp) !feof(fpp))//读取数据

{

fscanf(fp,"%d%s%*c%d",student.num,student.name,student.score);

fscanf(fpp,"%d",makeup);

if (makeup = 60)

{

student.score = 60;

}

else

{

if (makeup student.score)

{

student.score = makeup;

}

}

head = creat(head,student);

}

Print(head);

fclose(fp);

fclose(fpp);

}

求C语言函数大全

函数名: abort

功 能: 异常终止一个进程

用 法: void abort(void);

程序例:

#include stdio.h

#include stdlib.h

int main(void)

{

printf("Calling abort()\n");

abort();

return 0; /* This is never reached */

}

函数名: abs

功 能: 求整数的绝对值

用 法: int abs(int i);

程序例:

#include stdio.h

#include math.h

int main(void)

{

int number = -1234;

printf("number: %d absolute value: %d\n", number, abs(number));

return 0;

}

函数名: absread, abswirte

功 能: 绝对磁盘扇区读、写数据

用 法: int absread(int drive, int nsects, int sectno, void *buffer);

int abswrite(int drive, int nsects, in tsectno, void *buffer);

程序例:

/* absread example */

#include stdio.h

#include conio.h

#include process.h

#include dos.h

int main(void)

{

int i, strt, ch_out, sector;

char buf[512];

printf("Insert a diskette into drive A and press any key\n");

getch();

sector = 0;

if (absread(0, 1, sector, buf) != 0)

{

perror("Disk problem");

exit(1);

}

printf("Read OK\n");

strt = 3;

for (i=0; i80; i++)

{

ch_out = buf[strt+i];

putchar(ch_out);

}

printf("\n");

return(0);

}

函数名: access

功 能: 确定文件的访问权限

用 法: int access(const char *filename, int amode);

程序例:

#include stdio.h

#include io.h

int file_exists(char *filename);

int main(void)

{

printf("Does NOTEXIST.FIL exist: %s\n",

file_exists("NOTEXISTS.FIL") ? "YES" : "NO");

return 0;

}

int file_exists(char *filename)

{

return (access(filename, 0) == 0);

}

函数名: acos

功 能: 反余弦函数

用 法: double acos(double x);

程序例:

#include stdio.h

#include math.h

int main(void)

{

double result;

double x = 0.5;

result = acos(x);

printf("The arc cosine of %lf is %lf\n", x, result);

return 0;

}

函数名: allocmem

功 能: 分配DOS存储段

用 法: int allocmem(unsigned size, unsigned *seg);

程序例:

#include dos.h

#include alloc.h

#include stdio.h

int main(void)

{

unsigned int size, segp;

int stat;

size = 64; /* (64 x 16) = 1024 bytes */

stat = allocmem(size, segp);

if (stat == -1)

printf("Allocated memory at segment: %x\n", segp);

else

printf("Failed: maximum number of paragraphs available is %u\n",

stat);

return 0;

}

函数名: arc

功 能: 画一弧线

用 法: void far arc(int x, int y, int stangle, int endangle, int radius);

程序例:

#include graphics.h

#include stdlib.h

#include stdio.h

#include conio.h

int main(void)

{

/* request auto detection */

int gdriver = DETECT, gmode, errorcode;

int midx, midy;

int stangle = 45, endangle = 135;

int radius = 100;

/* initialize graphics and local variables */

initgraph(gdriver, gmode, "");

/* read result of initialization */

errorcode = graphresult(); /* an error occurred */

if (errorcode != grOk)

{

printf("Graphics error: %s\n", grapherrormsg(errorcode));

printf("Press any key to halt:");

getch();

exit(1); /* terminate with an error code */

}

midx = getmaxx() / 2;

midy = getmaxy() / 2;

setcolor(getmaxcolor());

/* draw arc */

arc(midx, midy, stangle, endangle, radius);

/* clean up */

getch();

closegraph();

return 0;

}

函数名: asctime

功 能: 转换日期和时间为ASCII码

用 法: char *asctime(const struct tm *tblock);

程序例:

#include stdio.h

#include string.h

#include time.h

int main(void)

{

struct tm t;

char str[80];

/* sample loading of tm structure */

t.tm_sec = 1; /* Seconds */

t.tm_min = 30; /* Minutes */

t.tm_hour = 9; /* Hour */

t.tm_mday = 22; /* Day of the Month */

t.tm_mon = 11; /* Month */

t.tm_year = 56; /* Year - does not include century */

t.tm_wday = 4; /* Day of the week */

t.tm_yday = 0; /* Does not show in asctime */

t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */

/* converts structure to null terminated

string */

strcpy(str, asctime(t));

printf("%s\n", str);

return 0;

}

函数名: asin

功 能: 反正弦函数

用 法: double asin(double x);

程序例:

#include stdio.h

#include math.h

int main(void)

{

double result;

double x = 0.5;

result = asin(x);

printf("The arc sin of %lf is %lf\n", x, result);

return(0);

}

函数名: assert

功 能: 测试一个条件并可能使程序终止

用 法: void assert(int test);

程序例:

#include assert.h

#include stdio.h

#include stdlib.h

struct ITEM {

int key;

int value;

};

/* add item to list, make sure list is not null */

void additem(struct ITEM *itemptr) {

assert(itemptr != NULL);

/* add item to list */

}

int main(void)

{

additem(NULL);

return 0;

}

函数名: atan

功 能: 反正切函数

用 法: double atan(double x);

程序例:

#include stdio.h

#include math.h

int main(void)

{

double result;

double x = 0.5;

result = atan(x);

printf("The arc tangent of %lf is %lf\n", x, result);

return(0);

}

函数名: atan2

功 能: 计算Y/X的反正切值

用 法: double atan2(double y, double x);

程序例:

#include stdio.h

#include math.h

int main(void)

{

double result;

double x = 90.0, y = 45.0;

result = atan2(y, x);

printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);

return 0;

}

函数名: atexit

功 能: 注册终止函数

用 法: int atexit(atexit_t func);

程序例:

#include stdio.h

#include stdlib.h

void exit_fn1(void)

{

printf("Exit function #1 called\n");

}

void exit_fn2(void)

{

printf("Exit function #2 called\n");

}

int main(void)

{

/* post exit function #1 */

atexit(exit_fn1);

/* post exit function #2 */

atexit(exit_fn2);

return 0;

}

函数名: atof

功 能: 把字符串转换成浮点数

用 法: double atof(const char *nptr);

程序例:

#include stdlib.h

#include stdio.h

int main(void)

{

float f;

char *str = "12345.67";

f = atof(str);

printf("string = %s float = %f\n", str, f);

return 0;

}

函数名: atoi

功 能: 把字符串转换成长整型数

用 法: int atoi(const char *nptr);

程序例:

#include stdlib.h

#include stdio.h

int main(void)

{

int n;

char *str = "12345.67";

n = atoi(str);

printf("string = %s integer = %d\n", str, n);

return 0;

}

函数名: atol

功 能: 把字符串转换成长整型数

用 法: long atol(const char *nptr);

程序例:

#include stdlib.h

#include stdio.h

int main(void)

{

long l;

char *str = "98765432";

l = atol(lstr);

printf("string = %s integer = %ld\n", str, l);

return(0);

}

c语言冒泡排序问题具体程序如下，有问题的部分是down和up函数。运行了你就知道问题所在#include

j循环倒了，i从0到n，j就要从n到i，stu[j]stu[j-1]交换他们，这样才是正确的

up()

{int i,j;

clrscr();

for(i=0;in-1;i++)

for(j=n-1;ji;j++)

if(stu[j].scorestu[j-1].score)

{k=stu[j];stu[j]=stu[j-1];stu[j-1]=stu[j];}

for(i=0;in;i++) printf(" %s %d\n",stu[i].num,stu[i].score);}

如何读懂C语言库函数

用法看文档

至于内容， 那个很多根本没内容， 当然没法“读懂”。