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定义好三角形的三个点,用line画线连接即可。
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示例如下:
Private Sub Form_Load()
Me.AutoRedraw = True
Dim x As Integer
Dim y As Integer
CurrentX = 1500
CurrentY = 500
Line -(3000, 2000), RGB(0, 0, 255)
Line -(1500, 2000), RGB(0, 0, 255)
Line -(1500, 500), RGB(0, 0, 255)
End Sub
运行效果:
Imports System.Drawing
Imports System.Drawing.Drawing2D
Public Class Form1
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim g As Graphics = PictureBox1.CreateGraphics
Dim hs As HatchStyle = HatchStyle.Cross
Dim sb As HatchBrush = New HatchBrush(hs, Color.Black, Color.White)
Dim p(3) As Point
p(0).X = 100
p(0).Y = 50
p(1).X = 0
p(1).Y = 100
p(2).X = 200
p(2).Y = 100
p(3).X = 100
p(3).Y = 50
g.FillPolygon(sb, p)
g.DrawPolygon(Pens.Black, p)
End Sub
End Class
VB系统的坐标原点在左上角,X轴的正方向是水平向右,而Y轴的正方向是垂直向下。所以,要绘制三角函数的曲线,自己可以通过改变点坐标的方法来实现,当然,VB.NET提供了相应的方法可以来实现坐标变换,也可以通过VB.Net的Graphics类提供的平移、旋转等转换来实现。
下面是我通过自己变换实现的示例,提供参考;我的环境是VB.NET 2010
Imports System.Math
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
'1,获得一个Graphics对象
Dim MyGraphics As Graphics
MyGraphics = PictureBox1.CreateGraphics
'2,定义一个Pen对象,用于绘制图形(轮廓线)
Dim MyPen As New Pen(Color.Black, 1)
'3,定义一个Brush对象,用于填充图形(如果需要填充的话)
Dim MyBrush As New SolidBrush(Color.Orange)
MyGraphics.DrawLine(MyPen, 0, 200, 700, 200)
End Sub
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
'1,获得一个Graphics对象
Dim MyGraphics As Graphics
MyGraphics = PictureBox1.CreateGraphics
'2,定义一个Pen对象,用于绘制图形(轮廓线)
Dim MyPen As New Pen(Color.Black, 1)
'3,定义一个Brush对象,用于填充图形(如果需要填充的话)
Dim MyBrush As New SolidBrush(Color.Orange)
'声明横向和纵向比例变量
Dim Heng As Integer = 20
Dim Zong As Integer = 50
'先获得正弦值,保存到点坐标数组
Dim MyPoints(700) As Point
Dim i As Integer
For i = 0 To 700
MyPoints(i) = New Point(i * Heng, 200 + Sin(i) * Zong)
Next
'采用绘制光滑线连接点的方式绘制曲线
MyGraphics.DrawCurve(MyPen, MyPoints)
End Sub
End Class
显示的效果图: