Bellman-Ford算法图解及手算过程详解——C++代码实现-创新互联

0. 《算法导论》讲解

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2. 代码实现（自己根据算法导论伪代码实现的代码，有错请指出，谢谢）

#include#includeusing namespace std;

const int n = 5;
const int INF = 0x3f3f3f3f;

typedef struct {int u;
	int v;
	int w;
}edge;

typedef struct {int d;
	int pi;
}record;

void printRecords(record records[]) {for (int i = 0; i< n; ++i) {if (records[i].d >= INF) {	cout<< "nan\t";
		} else {	cout<< records[i].d<< "\t";
		}
	}
	cout<< endl;
	for (int i = 0; i< n; ++i) {cout<< records[i].pi<< "\t";
	}
	cout<< endl<< endl;
}

vectortransform(int graph[n][n]) {vectoredges;
	for (int i = 0; i< n; ++i) {for (int j = 0; j< n; ++j) {	if (graph[i][j] != INF) {		edge temp = {i, j, graph[i][j]};
				edges.push_back(temp);
			}
		}
	}
	return edges;
}

void init(record records[n], vectoredges) {for (int i = 0; i< n; ++i) {records[i].d = INF;
		records[i].pi = -1;
	}
	records[0].d = 0;
}

void relax(int u, int v, record records[], int graph[n][n]) {if (records[v].d >records[u].d + graph[u][v]) {records[v].d = records[u].d + graph[u][v];
		records[v].pi = u;
	}
}

bool bellmanFord(int graph[n][n]) {vectoredges = transform(graph);
	record records[n];
	init(records, edges);
	printRecords(records);
	for (int i = 1; i< n; ++i) {for (int j = 0; j< edges.size(); ++j) {	relax(edges[j].u, edges[j].v, records, graph);
		}
		printRecords(records);
	}
	for (int k = 0; k< edges.size(); ++k) {int u = edges[k].u;
		int v = edges[k].v;
		if (records[v].d >records[u].d + graph[u][v]) {	return false;
		}
	}
	return true;
}

int main() {int graph[n][n] = {{INF, 6, INF, 7, INF},
		{INF, INF, 5, 8, -4},
		{INF, -2, INF, INF, INF},
		{INF, INF, -3, INF, 9},
		{2, INF, 7, INF, INF}
	};
	if (bellmanFord(graph)) {cout<< "true";
	} else {cout<< "false";
	}
	return 0;
}

3. 代码运行结果

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