Java数组求平均值代码 java怎么求数组的平均值

用JAVA编写，数组求平均值问题!

看看这个吧，简单的方法

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import java.util.Arrays;

public class Test3 {

public static void main(String[] args) {

int[] score = {6,8,7,9,4,7,8,6,8,6};

Arrays.sort(score);//排序，排序后头尾都不要，这样就去掉了最高分和最低分

int sum = 0;

for(int i=1; iscore.length-1; i++) {//从第数组二个元素取到倒数第二个

sum += score[i];

}

double average = sum/8.0;

System.out.println("平均：" + average);

}

}

java输入数组，求平均值，求标准值！

以int类型数组为例，其他类型的都类似.

用户输入的时候用逗号隔开数字就可以了

import java.util.Scanner;

public class Baidu {

public static void main(String[] args) {

int[] ary = getArrayFromInput();

double average = calcArrayAverage(ary);

System.out.println("Average is: " + average);

int count = 0;

for (int item : ary) {

if (item average) {

count++;

}

}

System.out.println("Total " + count

+ " numbers greater than average of given array");

}

private static int[] getArrayFromInput() {

System.out.println("Please input some digits, separate with ',': ");

Scanner scanner = new Scanner(System.in);

String[] digits = scanner.nextLine().split(",");

int[] array = new int[digits.length];

for(int i = 0; i digits.length; i++){

array[i] = Integer.parseInt(digits[i].trim());

}

return array;

}

private static double calcArrayAverage(int[] ary) {

double arySum = 0D;

for (int item : ary) {

arySum += item;

}

return arySum / ary.length;

}

}

-----------

Please input some digits, separate with ',':

12, 35, 28, 127, 96, 35

Average is: 55.5

Total 2 numbers greater than average of given array

Java中编程求一个整数数组的最大值、最小值、平均值和所有数组元素的和

package

com.work20081209.main;

/**

*

Java中编程求一个整数数组的最大值、最小值、平均值和所有数组元素的和

*

*/

public

class

TestArray

{

private

int

maxValue;

private

int

minValue;

private

double

aveValue;

private

int

sumValue;

public

TestArray(int[]

nums){

maxValue

=

nums[0];

minValue

=

nums[0];

aveValue

=

nums[0];

sumValue

=

nums[0];

for

(int

i

=

1;

i

nums.length;

i++)

{

if(nums[i]

maxValue){

maxValue

=

nums[i];

}

if(nums[i]

minValue){

minValue

=

nums[i];

}

sumValue

=

sumValue

+

nums[i];

}

aveValue

=

sumValue/nums.length;

}

public

void

print(){

System.out.println("最大值："+maxValue);

System.out.println("最小值："+minValue);

System.out.println("平均值："+aveValue);

System.out.println("和："+sumValue);

}

public

static

void

main(String[]

args)

{

int[]

index

=

new

int[]{4,1,5,3,2};

TestArray

ta

=

new

TestArray(index);

ta.print();

}

}

JAVA求数组平均值

这样应该行

public class Test20

{

public static double[] a1(double[]...a)

{

double[] suma=new double[a.length];

for(int i=0;ia.length;i++){

double sum=0;

for(int j=0;ja[i].length;j++){

sum+=a[i][j];

if(j==(a[i].length-1)){

suma[i]=sum/a[i].length;

}

}

}

return suma;

}

public static void main(String[] args) {

// TODO Auto-generated method stub

double a2;

double b2;

double c2;

double d2;

double a[]={90,85,66,51,69,78,88,94};

double b[]={68,88,81,90,65,74,64,46};

double c[]={68,90,85,88,68,70};

double d[]={60};

double[] avg=a1(a,b,c,d);

a2=avg[0];

b2=avg[1];

c2=avg[2];

d2=avg[3];

System.out.println(a2+","+b2+","+c2+","+d2);

}

}