vb.net隨機數 vbs 随机数

vb.net产生随机数

方法名称：next()；功能描述：返回一个0~2147483647之间的整数

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方法名称：next(i)；功能描述：返回一个0~i之间的整数

方法名称：next(i，j)；功能描述：返回一个i~j之间的整数

方法名称：Nextdouble()；功能描述：返回一个0~1之间的随机小数

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使用方法：

Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click

Dim rand = New System.Random()

MsgBox(rand.next().ToString())

End Sub

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产生N个不同数的话，我给你个我写的VB的代码，你稍微改下：

产生0-10的数：

Private Sub Command1_Click()

Randomize

Dim a(10) As Long

n = 10

For i = 0 To n

a(i) = Int(Rnd() * (n + 1))

For j = 0 To i - 1

If a(i) = a(j) Then

i = i - 1

Exit For

End If

Next

Next

For i = 0 To n

Print a(i)

Next

End Sub

VB.NET中怎么实现每单击一次按钮，文本框就多出现一个1-13的随机数字？

Dim n As Integer, b As Integer, a(13) As Integer

Private Sub Command1_Click()

If b 5 Then

b = b + 1

x = Int(n * Rnd()) + 1

Text1.Text = Text1.Text a(x) " "

a(x) = a(n)

n = n - 1

Else

Call Form_Load

End If

End Sub

Private Sub Form_Load()

Randomize

n = 13: b = 0

For i = 1 To 13

a(i) = i

Next i

Text1.Text = ""

End Sub

vb.net中产生三位正整数的随机数的程序写法

'项目：VB中产生在一定正整数范围内的不重复的随机数'作者：qq15495835Private Sub Command1_Click() Max = 100 '随机数上限值 Min = 1 '随机数下限值 Amount = 10 '产生号码数量(数量值应小于随机数上限值-随机数下限值)否则会产生死循环 ReDim a(Amount) Randomize For i = 0 To Amount a(i) = Int((Max - Min + 1) * Rnd + Min) For j = 0 To i If i j And a(i) = a(j) Then i = i - 1 Next Next Text1 = Join(a, vbCrLf)End Sub'请采纳参考！谢谢！