java线程推塔代码 java线程死锁代码

java线程的经典代码

package threadgroup;

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class ThreadDemo3 extends Thread {

private String name;

private int delay;

public ThreadDemo3(String sname, int i_delay) {

name = sname;

delay = i_delay;

}

public void run() {

try {

sleep(delay);

} catch (InterruptedException e) {

}

System.out.println("多线程测试！\n" + name + "\n" + delay);

}

}

public class testMyThread {

public static void main(String[] args) {

ThreadDemo3 th1,th2,th3;

th1 = new ThreadDemo3("线程1", (int) (Math.random() * 900));

th2 = new ThreadDemo3("线程2", (int) (Math.random() * 900));

th3 = new ThreadDemo3("线程3", (int) (Math.random() * 900));

th1.start();

th2.start();

th3.start();

}

}

package threadgroup;

public class threadDemo {

public static void main(String[] args) {

Thread t = Thread.currentThread();

t.setName("你好吗？");

System.out.println("正在进行的Thread是：" + t);

try {

for (int i = 0; i 5; i++) {

System.out.println("我不叫穆继超" + i);

Thread.sleep(3000);

}

} catch (Exception e) {

// TODO: handle exception

System.out.println("Thread has wrong" + e.getMessage());

}

}

}

package threadgroup;

public class threadDemo2 implements Runnable {

public threadDemo2() {

Thread t1 = Thread.currentThread();

t1.setName("第一个主进程");

System.out.println("正在运行" + t1);

Thread t2 = new Thread(this, "");

System.out.println("在创建一个进程");

t2.start();

try {

System.out.println("使他进入第一个睡眠状态");

Thread.sleep(2000);

} catch (InterruptedException e) {

System.out.println("Thread has wrong" + e.getMessage());

}

System.out.println("退出第一个进程");

}

public void run() {

try {

for (int i = 0; i 5; i++) {

System.out.println("进程" + i);

Thread.sleep(3000);

}

} catch (InterruptedException e) {

// TODO: handle exception

System.out.println("Thread has wrong" + e.getMessage());

}

System.out.println("退出第二个进程");

}

public static void main(String[] args) {

new threadDemo2();

}

}

求一个JAVA多线程例子，最好有代码，谢谢啦！

package a.b.test;

import java.util.Date;

import java.util.concurrent.Callable;

import java.util.concurrent.ExecutorService;

import java.util.concurrent.Executors;

import java.util.concurrent.Future;

public class Calculate1000 implements CallableInteger{

public Calculate1000(){}

public Calculate1000(int a, int b){

this.a = a;

this.b = b;

}

int a;

int b;

/**

* @param args

* @throws Exception

*/

public static void main(String[] args) throws Exception {

//同步

Calculate1000 ca1 = new Calculate1000();

Date ds1 = new Date();

int result = 0;

for(int i = 1 ; i = 1000 ; i++){

result = ca1.add(i, result);

}

System.out.println(result);

System.out.println("同步用时" + (new Date().getTime() - ds1.getTime()) + "MS");

//异步

Date ds2 = new Date();

result = 0;

ExecutorService es = Executors.newFixedThreadPool(2);

FutureInteger future1 = es.submit(new Calculate1000(1,500));

FutureInteger future2 = es.submit(new Calculate1000(501,1000));

result = future1.get() + future2.get();

System.out.println(result);

System.out.println("异步用时" + (new Date().getTime() - ds2.getTime()) + "MS");

es.shutdown();

}

private int add(int a, int b) throws Exception{

Thread.sleep(10);

return a + b;

}

@Override

public Integer call() throws Exception {

int res = 0;

for(int i = a ; i = b ; i++){

res = this.add(res, i);

}

return res;

}

}

楼主你试一下这段代码行不行，行的话请采纳！

java多线程编程代码如下，输出结果如下:

首先，你同步的是具体的某个Test实例， 对于那个实例来说，实际上只有一个线程访问了那个代码块，但是sum和other却是多个线程同时去进行访问，实际上这是不安全的，如果你想实现每次都输出10000的效果，那么正确的应该是在Test.class上加锁，而不是获取Test实例的锁，修改后的代码如下：

public class Test extends Thread {

public static int sum = 10000;

public static int other = 0;

public void getMoney() {

synchronized (Test.class) {

System.out.println(Thread.currentThread().getName() + " 开始执行");

sum = sum - 100;

System.out.println("sum-100");

other = other + 100;

System.out.println("other+100");

System.out.println(sum + other);

System.out.println(Thread.currentThread().getName() + " 执行完成");

}

}

public void run() {

getMoney();

}

public static void main(String[] agrs) {

Thread t[] = new Thread[10];

for (int i = 0; i = 9; i++) {

t[i] = new Test();

t[i].start();

}

}

}

// 上面代码能得到你的结果