大橙子网站建设,新征程启航

为企业提供网站建设、域名注册、服务器等服务

C语言实现万年历

C语言实现的万年历显示,按下上下左右按键来更换日期和年份,供大家参考,具体内容如下

做网站、网站设计服务团队是一支充满着热情的团队,执着、敏锐、追求更好,是创新互联的标准与要求,同时竭诚为客户提供服务是我们的理念。创新互联把每个网站当做一个产品来开发,精雕细琢,追求一名工匠心中的细致,我们更用心!

#include  
#include  
#include  
#include 
typedef struct today 
{ 
 int day; 
 int month; 
 int year; 
} today; 
 
int day_cankao[2][13]={ 
 {0,31,28,31,30,31,30,31,31,30,31,30,31}, 
 {0,31,29,31,30,31,30,31,31,30,31,30,31} 
}; 
char *week[]= 
{ 
 "Sun","Mon","Tue","Wen","Thu","Fir","Sat" 
}; 
struct tm *todayuse;//struct tm定义c语言中time的结构体 
today today_current; 
int getweekday(today today_usenow) 
{ 
 // w = y + [y/4] + [ c/4 ] – 2c+ [13 * (m+1) / 5] + d – 1 
 //其中,c是年份的前两位,y是年份的后两位,m是月份,d是日期,这里需要注意的是,如果是1月和2月,c和y需要按照上一年来取值。 
 int w=0; 
 
 int year=today_usenow.year; 
 int month=today_usenow.month; 
 if(today_usenow.month==1 || today_usenow.month==2) 
 { 
 month+=12; 
 year--; 
 } 
 int y=year%100; 
 int c=year/100; 
 int m=month; 
 
 w=y + y/4 + c/4 - 2*c+ 26* (m+1) / 10 + today_usenow.day -1; 
 while(w<0) 
 { 
 w+=7; 
 } 
 return (w%7); 
 
} 
int is_leap(int year) 
{ 
 
 if( (year%4==0 && year%100!=0) || (year%400==0)) 
 { 
 return 1; 
 } 
 else 
 return 0; 
} 
int getmonthdays(int year,int month) 
{ 
 return day_cankao[is_leap(year)][month]; 
} 
 
 
void print_calendar(today today_usenow) 
{ 
 printf("---------------------------\n"); 
 printf("Sun Mon Tue Wen Thu Fir Sat\n"); 
 int firstday=0; 
 today today_usehere=today_usenow; 
 today_usehere.day=1; 
 int day=getweekday(today_usehere);//日期前 
 //int daysuseafter 
 int days=getmonthdays(today_usenow.year,today_usenow.month);//月总数 
 // 0 1 2 3 4 5 6 // 6 
 int daysbefore=0; 
 if((today_usenow.month-1)==0) 
 { 
 //现在为1月,去年的十二月份 
 daysbefore=getmonthdays(today_usenow.year-1,12); 
 // printf("%d is",daysbefore); 
 } 
 else 
 { 
 
 
 daysbefore=getmonthdays(today_usenow.year,today_usenow.month-1); 
 } 
 int daysbefoeit=daysbefore-day+1; 
 printf(""); 
 int count=1; 
 if(day==0) 
 { 
 daysbefoeit-=7; 
 for(int i=0;itm_year); 
 printf("Month: %d\n", 1+p->tm_mon); 
 printf("Day: %d\n", p->tm_mday); 
 printf("Hour: %d\n", p->tm_hour); 
 printf("Minute: %d\n", p->tm_min); 
 printf("Second: %d\n", p->tm_sec); 
 printf("Weekday: %d\n", p->tm_wday); 
 printf("Days: %d\n", p->tm_yday); 
 printf("Isdst: %d\n", p->tm_isdst); 
 */ 
 
 //printf("%d",day_cankao[0][12]); 
 today_current.year=1900+p->tm_year; 
 today_current.month=1+p->tm_mon; 
 today_current.day= p->tm_mday; 
 today use=today_current; 
 int c1,c2; 
 printf(" %d 年 %d 月 %d 日\n",today_current.year,today_current.month,today_current.day); 
 print_calendar(today_current); 
 while(1) 
 { 
 c1 = getch(); 
 if(c1==27) 
 { 
 printf("您已经退出系统"); 
 break; 
 } 
 if(c1==110) 
 { 
 printf(" %d 年 %d 月 %d 日\n",today_current.year,today_current.month,today_current.day); 
 //printf("%d \n",getweekday(today_current)); 
 
 print_calendar(today_current); 
 use=today_current; 
 continue; 
 } 
 c2 = getch(); 
 //printf( "%d %d",c1,c2); 
 
 if(c1==224 && c2==72) 
 { 
 use.month+=1; 
 if(use.month==13) 
 { 
 use.month=1; 
 use.year+=1; 
 } 
 printf(" %d 年 %d 月 %d 日\n",use.year,use.month,use.day); 
 //printf("%d \n",getweekday(today_current)); 
 
 print_calendar(use); 
 
 } 
 if(c1==224 && c2==80) 
 { 
 use.month-=1; 
 if(use.month==0) 
 { 
 use.month=12; 
 use.year-=1; 
 } 
 printf(" %d 年 %d 月 %d 日\n",use.year,use.month,use.day); 
 //printf("%d \n",getweekday(today_current)); 
 
 print_calendar(use); 
 } 
 if(c1==224 && c2==75) 
 { 
 use.year-=1; 
 printf(" %d 年 %d 月 %d 日\n",use.year,use.month,use.day); 
 //printf("%d \n",getweekday(today_current)); 
 
 print_calendar(use); 
 } 
 if(c1==224 && c2==77) 
 { 
 use.year+=1; 
 printf(" %d 年 %d 月 %d 日\n",use.year,use.month,use.day); 
 //printf("%d \n",getweekday(today_current)); 
 
 print_calendar(use); 
 } 
 printf("\n"); 
 printf("按上下按钮,进行月份变换\n"); 
 printf("按左右按钮,进行年份变换\n"); 
 printf("按ESC按键,退出系统\n"); 
 printf("按N按钮,查看当前日期\n"); 
 } 
 //上 224 72 
 //下 224 80 
 //左 224 75 
 //右 224 77 
 //esc 27 
 // n 110 
 
 return 0; 
} 

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持创新互联。


网站栏目:C语言实现万年历
当前路径:http://dzwzjz.com/article/jiiogj.html
在线咨询
服务热线
服务热线:028-86922220
TOP